Odpowiedzi

2009-12-13T14:43:29+01:00
Cp=ms*100%/mr
ms=cp*mr/100=20*120/100=24g
cp2=ms*100%/mr1
mr1=ms*100%/cp2=24*100/25=96g
mw=mr-mr1=120-96=24g
należy odparować 24 g wody
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2009-12-13T14:47:14+01:00
Mr = 120g
c = 20%
ms = 20% * 120g = 24g

c = ms/mr*100%
25% = ms/(mr-x)*100% (x - masa wody którą odparowujemy)
25% = 24g/(120g-x)*100%
25/100 = 24/(120g-x)
25(120g-x) = 2400g
3000g - 25x = 2400g
25x = 3000g - 2400g
25x = 600g
x = 24g
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