Odpowiedzi

2009-12-13T21:33:50+01:00
A=v/t v=36km/h=10m/s
s=a*t^2/2

s=vt/2
s=10*5/2
s=25 [m]
2009-12-13T21:35:14+01:00
Dane:
v = 36km/h = 10m/s
t = 5s

Szukane:
s = ?

a - przyspieszenie
a = Δv/t
a = (10m/s)/5s
a = 2m/s^2

S = v*t - (at^2)/2 = 50 - 25 = 25m

lub S = 1/2 V*t = 5*5 = 25m

Odp. Droga hamowania wynosi 25m