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  • Użytkownik Zadane
2009-09-08T22:19:11+02:00
3/(x+2)=(3∙2∙(x-4))/2(x+2)(x-4) =6(x-4)/2(x+2)(x-4)
2/(x+2)=2(x-2)/(x+2)(x-2) =(2x-4)/(x^2-4)
(x+1)/(x+3)=2x(x+1)/2x(x+3) =(2x^2+2x)/(2x^2+6x)
(3x-2)/(x+1)=(3x-2)^2/(x+1)(3x-2) =(9x^2-12x+4)/(〖3x〗^2+x-2)
2/(x-2)=2(x^2+2x+4)/(x-2)(x^2+2x+4) =(bez zmian)/(x^3+8)