Odpowiedzi

2009-12-14T22:18:21+01:00
1-[-5a+[3+4a]]=1-(-5a+3+4a)=1-(-a+3)=1+a-3=a-2

-1,8a-[-[a+1]+[0,8a-1]]= -1,8a-(-a-1+0,8a-1)=-1,8a-(-0,2a-2)=
=-1,8a+0,2a+2=-1,6a+2

:)
2009-12-14T22:21:40+01:00
1-[-5a+[3+4a]]=1-(-5a+3+4a)=1+a-3=-2+a


-1,8a-[-(a+1)+(0,8a-1)]=-1,8a-(-a-1+0,8a-1)=
=-1,8a+a+1-0,8a+1=2-1,6a
2009-12-14T22:21:13+01:00
1-[-5a+[3+4a]]=1-[-5a+3+4a]=1-[-a+3]=1+a-3= a-2

-1,8a-[-[a+1]+[0,8a-1]]= -1,8a-[-a-1+0,8a-1]=
-1,8a-[-0,2a-2]=-1,8a+0,2a-2= -1,6a+2