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2009-12-15T15:16:56+01:00

2x²-3x-2³ = 0
x(2x-3)-8 = 0

x³+x² = 0
x²(x+1)=0

x³+x+2 = 0
x(x²+1) + 2 = 0

16x⁵-x = 0
x(16x⁴)=0
x(2x)⁴=0

(4x-5)(x²-4)=(3x²-12)(3+2x)
(4x-5)(x²-4)=3(x²-4)(3+2x) /: (x²-4)
(4x-5)=3(3-2x)
(4x-5) - 3(3-2x) = 0
4x - 5 - 9 + 6x = 0
10x - 14 = 0