Proszę to wazne
rozwiaz;

[-3-5][2]-2[2]= dwojki w nawiasie oznaczaja do potegi 2
4 1/3~[-3]-[-4]= ~ mnozenie
-2[3]-[-4,2]~2/7-
[1-1,2]:0,04=
[3-5][3]~[-6]=
5[2]-8[2]:[-4]=
-2[2]-[-4]~1 5/12=
0,27:[-0,03]=
-5-1 1/3~6=
[-8+2]~4/5=
1-[-4]:4/5=
7[0]-7[2]=
90-7[2]
-1= kreska ulamkowa nad-1
[-10][2]+26=
-2 1/5~[10]-31=
5/4~2,2-7 3/4=
[-6][2]-[-5]=

dzieki prosze szybko!

2

Odpowiedzi

2009-12-16T13:49:08+01:00
[-3-5]²-2²=[-8]²-4=64-4=60
4 1/3*[-3]-[-4]=13/3*[-3]+4=-13+4=-9
-2³-[-4,2]*2/7=-8-[-42/10]*2/7=8+42/10*2/7=80/10+42/10*2/7=122/10*2/7=122/35=3 17/35
[1-1,2]:0,04=-0,2:4/100=-2/10*100/4=-5
[5-3]³*[-6]=2³*[-6]=8*[-6]=-48
5²-8²:[-4]=25-64:[-4]=-39:[-4]=39/4=9 3/4
-2²-[-4]*1 5/12=4-[-4]*17/12=4-17/3=4-5 2/3=-1 2/3
0,27:[-0,03]=27/100:[-3/100]=27/100*[-100/3]=-27/3=-9
-5-1 1/3*6=-5-4/3*6=-5-6=-11
[-8+2]*4/5=-6*4/5=-24/5=-4 4/5
7⁰-7²=1-49=48
90-7² 90-49 41
------=--------=---------=41:[-1]=-41
-1 -1 -1

[-10]²+26=100+26=126
-2 1/5*10-31=-11/5*10-31=-22-31=-53
5/4*2,2-7 3/4=5/4*22/10-7 3/4=11/4-7 3/4=2 2/4-7 3/4=-5 1/4
[-6]²-[-5]=36+5=41
2009-12-16T14:35:54+01:00
A) (-3-5)²-2²=(-8)²-4=64-4=60
b)4⅓×(-3)-(-4)=13/3×(-3)+4=13+4=17
c)(-2)³-(-4)×2/7=-8+4,2×2/7=-3,8×2/7=(-38/10)×2/7=38/35=1 1/35
d)(1-1,2):0,04=-0,2:0,04=-5
e)(3-5)³×(-6)=(-2)³×(-6)=-8×-6=48
f)5²-8²:(-4)=25-64:(-4)=25+16=41
g)-2²-(-4)×1 5/12=4+4×1 1/14+4×17/12=4+17/3=4+3 2/3=7 2/3
h)0,27:(-0,03)=(-9)
i)-5-1 1/3×6= -5-4/3×6=-5-8=-13
j)(-8+2)×4/5=-6×4/5=-25/5= -4 4/5
k)1-(-4):4/5=1+4:4/5=5:4/5=5×4/5=25/4=6 1/4
l)1-7²=1-49=-48
m)90-7²=90-49=41
n)(-10)²+26=100+26=126
o)-2 1/5×10-31= -11/5×10-31=-22-31=-53
p)5/4×2,2-7 3/4=5/4×22/10-31/4=22/8-31/4=22/8-62/8=-40/8=-5
r)-6²+5=36+5=41