Odpowiedzi

2009-12-16T18:49:32+01:00

NaOH = 23u + 16u + 1u = 40u

Ca(OH)_{2} = 40u + ( 16u + 1u) x 2 = 74u

12 3 12
2009-12-16T18:50:33+01:00
NaOH mcz. =23u+16u+1u = 40 u
Ca(OH)2 = 40u+ 2*16u +2*1u= 74 u
10 4 10
2009-12-16T18:52:51+01:00
M cząsteczkowa NaOH => 23u + 16u + 1u = 40 u

M cząsteczkowa Ca(OH)₂ = 40u + (2*16u) + (2*1u)= 74 u
10 4 10