Odpowiedzi

2009-12-16T23:28:36+01:00
A)[(2¼)-¹-6-²]= [(9/4)⁻¹ -6/1 ⁻²]= [(4/9)¹ - 1/6²] = 4/9-1/36 = 16/36 -1/36= 15/36

b)[(4½)-²+(1½)-²]-¹=[(9/2)⁻²+(3/2)⁻²]⁻¹= [ (2/9)²+ (2/3)²]⁻¹ =
[4/81 + 4/9]⁻¹ = ( 4/81 + 36/81)⁻¹= [-32/81]⁻¹=81/32¹= 81/32

c)[(2¾)-¹-6-²]-² = [(11/4)⁻¹-6/1⁻²]⁻²=[4/11-1/6 ²]²= [4/11 - 1/36]² = kurde dokoncz sobie to bo nie moge znalesc wspolnego mianownika