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2009-12-17T19:02:24+01:00
Czyli mamy C6H13COOH i mamy zrobic tego sklad procentowy

M = 7*12+14+2*16 g/mol = 130 g/mol

X(C) = 7*12 g/mol / 130g/mol * 100% = 64,62%
X(H) = 14 g/mol / 130 g/mol * 100% = 10,77%
X(O) = 2*16g/mol / 130g/mol *100% = 24,62%

czyli mamy 64,62% C, 10,77% H i 24,62% O