Odpowiedzi

2009-12-18T13:24:51+01:00
2009-12-18T13:38:05+01:00
X=√6+2, y=√6-√2, z=?

x²+y²=z²

(√6+2)²+(√6-√2)²=z²
6+4√6+4+6-2√12+2=z²
18+4√6-2√12=z²
18+√96-√48=z²
z²=20,87
z=4,56
2009-12-18T14:05:46+01:00
X²+y²=z²

(√6+2)²+(√6-√2)²=z²

(√6+2)*(√6+2)+(√6-√2)*(√6-√2)=z²

√36+2√6+2√6+4+√36-√12-√12+√4=z²

6+√24+4+6-√24+2=z²

18=z²

√18=z

3√2=z