Odpowiedzi

2009-12-19T18:06:53+01:00
((3√2-1)⁶-(√2+1)²)/8 =
=((3√2-1)⁶-(3+2√2))/8=
=((3√2-1)⁶-3-2√2)/8=
=(8585-4770√2-3-2√2)/8=
=1072,75-596,5√2
1 4 1
2009-12-19T20:08:00+01:00
A moim zdaniem:

((3√2-1)⁶-(√2+1)²)/8=
(5832+1-2-1)/8=
5830/8= 728,75