Odpowiedzi

2009-12-20T16:04:14+01:00
Y- bilet normalny
x- bilet ulgowy

3y+2x=34
y+3x=23

3y+2x=34
y=23-3x

3(23-3x)+2x=34
y=23-3x

69-9x+2x=34
y=23-3x

-7x=34-69
y=23-3x

-7x=-35/(-7)
y=23-3x

x=5
y=23-3*5

x=5
y=23-15

x=5
y=8
2009-12-20T16:06:44+01:00
X- ulgowy - 5
y - normalny - 8

3y + 2x = 34
y = 3x = 23 / * (-3)

3y + 2x = 34
-3y - 9x = -69

3y +2x - 3y - 9x = 34 - 69
-7x = -35 / : (-7)
x=5

y + 3*5=23
y+15=23
y=23-15
y=8