Odpowiedzi

2009-12-25T17:54:04+01:00

20g xg
C3H8+4,5O2->3CO2+4H2O
44g 132g

MC3H8=3*12 u+8u=44u
mCO2=12u+2*16u=44u*3 (bo 3 mole)=132u

20g C3H8->XgCO2
44g C3H8->132g CO2
X=60g