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2009-12-20T19:37:32+01:00
(5x+2)² = 20x
25x²+20x+4=20x
25x²+4=0
delta=400
√200=20
x₁=(-0-20)/50=-20/50=-2/5
x₂=(-0+20)/50=20/50=2/5
(2x-1)(x+2) = 3x-2
2x²-4x-x-2=3x-2
2x²-8x=0
delta=64
√64=8
x₁=(-8-8)/4=-4
x₂=0
(1-3x)² = 1-6x
1-6x+9x²-1+6x=0
9x²=0
czyli0
(3+2x)² = (3x+2)²+10
9+12x+4x²=9x²+12x+4+10
-5x²-5=0
delta=-100
brak pierwiastków
(5x-2)(3-x) = -6(1-x)(1+x)
15x-5x²-6+2x+6-6x²=0
-11x²+17x=0
delta=289
√289=17
x1=(-17-17)/-22=34/22
x2=0
x+9 = (x-3)²
x+9=x²-6x+9
-x²+7x=0
delta=49
√49=7
x1=7
x2=0
(4x-6)² = (x-4)(x-9)
16x²-48x+36-x²+9x+4x-36=0
15x²-35x=0
delta=1225
√1225=35
x1=(35-35)/30=0
x2=70/30=7/3
(x-2)(x+2) = 5
x²-4-5=0
x²-9=0
x=3 x=-3