Odpowiedzi

2009-12-20T21:31:06+01:00
(4-2x)²-2(2x-3)(2x+3)-4(-3x+1)>0
16-16x+4x²-2(4x²-9)+12x-4>0
16-16x+4x²-8x²+18+12x-4>0
30-4x-4x²>0
-4x²-4x+30>0
Δ=b²-4ac
Δ=16-4×(-4)×30
Δ=16+480= 496
√Δ=√16×31
√Δ=4√31
x₁= -b - √Δ = 4 - 4√31 = 4(1-√31)
x₂= -b+ √Δ = 4+4√31 =4 ( 1+ √31)
rozw. x∈ ( x₁ , x₂)