Odpowiedzi

2009-09-14T21:12:27+02:00
(2x-1)(x²-3)-(1-2x)(1-2x²)=(2x-1)(x²-3)-[-(2x-1)(1-2x²)]=
(2x-1)(x²-3)+(2x-1)(1-2x²)=(2x-1)(x²-3+1-2x²)=(2x-1)(-2-x²)
2009-09-14T21:17:02+02:00
(2x-1)(x²-3)-(1-2x)(1-2x²)=
(2x-1)(x²-3)+(2x-1)(1-2x²)=
(2x-1)[x²-3+1-2x²]=
(2x-1)(-x²-2)=
-(2x-1)(x²+2)