Odpowiedzi

2009-12-26T22:06:18+01:00
Y=x^-1/3
y'= (-1/3) * x^[(-1/3)-1]
y'=(-1/3)x^(-4/3)
2009-12-26T22:24:55+01:00
Y=x^⁻⅓

y'=-⅓ x^ ⁻⅓-1
y'=-⅓ x ^-1⅓
2 1 2
2009-12-26T22:32:40+01:00
Y=x^(⁻⅓)

y'=-⅓ x^ (⁻⅓ ⁻ ¹)
y'=-⅓ x ^(-1⅓)
y'=-⅓ x ^(-⁴/³)
2 3 2