Odpowiedzi

2009-12-29T09:49:30+01:00
10(5-y)*(6-x)=100
(50-10y)(6-x)=100
50*6-50*x-10y*6-10y*(-x)=100
300-50x-60y+10xy=100
2009-12-29T11:24:45+01:00
10(5-y)*(6-x)=100
10(30-5x-6y+xy)=100
300-50x-60y+10xy=100
2009-12-29T14:28:25+01:00
10(5-y)*(6-x)=100
(50-10y)*(6-x)=100
300-50x-60y+10xy=100