Odpowiedzi

  • Użytkownik Zadane
2009-12-31T20:55:14+01:00
Ad 1.
log90 = log10 + log9 = 1 + log3³ = 1 + 2 log3 = 1 + 2 log(12/4) =
= 1 + 2 × (log12 - log4) = 1 + 2 × (log12 - log2²) = 1 + 2 × (log12 - 2log2) = 1 + 2 × (a - 2b) = 1 + 2a - 4b