Odpowiedzi

Najlepsza Odpowiedź!
  • Użytkownik Zadane
2010-01-03T12:58:41+01:00
32.
a)
mCxH2x-2 = 82u
86u = 12x + 1 * 2x - 2
86u = 12x + 2x - 2
864u = 14x
x = 6
wzór sumaryczny : C6H10
Nazwa : heksyn

b)
m CxH2x-2 = m C6H10
86u = (12*6) : (1 * 10 - 2) = 72 : 10 = 36 : 5

33.
a)
C4H8
mC4H8 = 12u * 4 + 8 * 1u = 56u
m C4 = 12u * 4 = 48u
m H8 = 8u

% C4
100% - 56u
x - 48u
x = 85,71%

% H8
100% - 56u
x - 8u
x = 14,29%

b)
C4H6
m C4H6 = 12u * 4 + 4u = 54u
m C4 = 48u
m H6 = 6u

% H6
100% - 54u
x - 6u
x = 11,11%

% C4
100% - 54u
x - 48u
x = 88,89%

34.
a) C2H4, ETYLEN
b)
mC2H4 = 12*2 + 1*4 = 28u
m C2 = 24u
m H4 = 4u

% C
100% - 28u
x - 24u
x = 85,71%

% H
100% - 28u
x - 4u
x = 14,29%
c)
m C2H4 = 2*12 + 1*4 = 28u
28u = 12u*2 : 1u*4 = 24u : 4u = 6 :1

37.
C2H4 + 2O2 -> 2CO + 2 H20
C2H4 + O2 -> 2C + 2 H20
C2H4 + 3O2 -> 2CO2 + 2 H20
C2H4 + Cl2 -> c2h4cL2
C2H4 + Br2 -> ...
n C3H6 -> CH2 = CH - CH3
CH2 = CH2 + HCl -> C2H5Cl
ch2 = ch2 + h2 -> ch3 - ch3

39.
HC ≡ CH
1, 3, 1

40.
m C2H2 = 2 * 12 = 26u
m C2 = 24u
m H2 = 2u

100% - 93,31% = 7,69%
26u - 100%
24u - c %
x = 92, 31%


42.
2 C2H2 + 5O2 -> 4CO2 + 2H20
2C2H2 + O2 -> 4C + 2H20
2C2H2 + 302 -> 4CO + 2H20



4 3 4