Odpowiedzi

2009-09-17T15:46:32+02:00
2 cm = 1/3h trojkata
h= 6 cm

(2 cm)² + b²=(4 cm)²
b²=(12 cm)²
b=2√3

bok trojkata = 2×2√3
obwod (l) = 12√3
1 1 1
2009-09-17T16:21:10+02:00
R=2=1/3 h
2/3 h =4
2+4=6 =h(wysokosc)
6=a√3
a=6/√3 × √3/√3=2√3
Obw=2√3+2√3 + ( 2×4√3)=4√3+8√3=12√3
2 2 2