Odpowiedzi

2010-01-04T20:30:34+01:00
MCuO= 64u+16u=80u
mFe2O3=2*56u+3*16u=112+48=160u
mNaCO3=23u+12u+3*12u=71u
mH2SO4=2*1u+32u+4*16u=98u
mCa(OH)2=40u+(16+1)2=40u+17u*2=40u+34u=74u
mFe2(SO3)3=2*56u+(32u+3*16u)3=112u+(32u+48u)3=112u+80u*3=240u+112u= =352u
1 5 1
2010-01-04T20:33:04+01:00
MFe2O3=2*56u+3*16u=112u+48u=160u
mCuO= 64u+16u=80u
mNaCO3=23u+12u+3*16u=23u+12u+48u=83u
mH2SO4=2*1u+32u+4*16=2u+32u+64u=98u
mCa(OH)2=40u+2*16u+2*1u=40u+32u+2u=74u
mFe2(SO3)3=2*56u+3*32u+9*16u=112u+96u+144u=352u
3 4 3