Odpowiedzi

2010-01-07T14:07:58+01:00
2x-5/ x-4 = x /* x - 4
2x - 5 = x² - 4x
-x² + 2x +4x - 5 = 0
-x² + 6x - 5 = 0
Δ = b² - 4ac = 36 - 20 = 16
√Δ = 4
x₁ = (-b - √Δ) : 2a = -6 - 4 : -2 = - 10 : -2 = 5
x₂ = (-b + √Δ) : 2a = -6 + 4 : -2 = - 2 : -2 = 1
2010-01-07T14:09:37+01:00
2x-5/ x-4 = x /*x-4
2x-5=x (x-4)
2x-5=x²-4x
-x²+2x+4x-5=0
Δ=b²-4ac
Δ=36-4×(-1)×(-5)=36-20=16
√Δ=4
x₁=-b-√Δ/2a=¹⁰/₂=5
x₂=-b+√Δ/2a=⁻²/₋₂=1