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2010-01-08T17:19:24+01:00
(b√2+1)² - (1-b√2)²+ (b√2-3)*(b√2+3) =
=(2b²+2b√2+1)-(1-2b√2+2b²)+(2b-9)=
=2b²+2b√2+1-1+2b√2-2b²-9=2b-9

3(a-2b)² + 6(a+b)²-9(a-√6)*(a+√6) =
=3(a²-4ab+4b²)+6(a²+2ab+b²)-9(a²-6)=
=3a²-12ab+12b²+6a²+12ab+6b²-9a²+54=
=18b²+54