Odpowiedzi

2010-01-08T21:19:49+01:00
M1-0,2kg
T1= -20C
T2-80C
Tk-50C
c1-2100J/kg*C
c2- 4200J/kg*C
m2=?

delta T1= 50C+20C=70C
deltaT2= 80C-50C=30C

Q=cm *delta T1
Q= 2100J/kg*C * 0,2kg * 70C= 29400J
Q=29400J

Q=c2m2deltaT2C

m=Q/c*delta T
m= 29400J/4200J/kg*C * 30C= około 0,23kg
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