Odpowiedzi

2010-01-10T03:04:51+01:00
Log49 7 =log49 49^1/2=1/2 log49 49=1/2*1=1/2
log 0,2 625=log0,2 5^4=4*log0,2 (1/5)^-1=-4*log0,2 (2/10)=-4*1=-4
log√3 27=log√3 (√3)^6=6*log√3 √3=6*1=6
log2 144 - log2 9 = log2(144/9)=log2 (12/3)^2=2log2 4=2log2 2^2=2*2log2 2=
=4*1=4
log3 54+log3 1,5=log3 (54/1,5)=log3 36=log3 6^2=2*log3 6=2*log3 (2*3)=
=2*(log3 3 +log3 2)=2*(1+log3 2)=2+2log3 2=2+log3 2^2=2+log3 4

^-do potęgi
4 3 4