Odpowiedzi

2010-01-10T16:44:06+01:00
A) 7ײ-4×-6ײ+4-ײ+5×= 1x + 4
b) -2(3a-2b)-4a²(2-3a+2b)= -6a+4b-8a2+12a3-4a2b
c) (4-×)(2×+5)-4= 8x+20-2x2-5x=3x+20-2x2
d) (4-2×)(3×-3)-2×(3×+1)=12x-12-6x2+6x-6x2-2x=16x-12-12x2
2010-01-10T16:47:19+01:00
A) 7ײ-4×-6ײ+4-ײ+5×= x +4
b) -2(3a-2b)-4 a²(2-3a+2b)=-6a+4b-8a²12a³-8a²b
c) (4-×)(2×+5)-4=-2x²+3x+16
d) (4-2×)(3×-3)-2×(3×+1)=-12x²+16x -12
2010-01-10T16:48:08+01:00
A=x+4
b=-6a+4b-8a2 + 12a3 - 8ba2
c-nie wiem;( d tak samo:(