Odpowiedzi

2009-09-24T22:12:00+02:00
A² = 3[(1/2 * 12 * 18 + (12+18)*5,6/2)
a² = 576
a = 24

Ob = 4a = 96
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2009-09-24T22:24:53+02:00
P= e*f/2=12*18/2=108 pole deltoidu
P=(a+b)*h/2=(12+18)*5,6/2=84 pole trapezu
108+84=192
192*3=576
24*24=576
24 bok kwadratu
Obw=4*24=96
1 5 1