Odpowiedzi

2010-01-13T10:42:01+01:00
[x(x-2)]:3-(x²-x/2)=x-3/4-x*(x/6+1)
x² - 2x/3 - (x²-x/2) = x - 3/4 - x²/6 - x / *12
4 * (x² - 2x) - 12x² + 6x = 12x - 9 - 2x² - 12x
4x² - 8x - 12x² + 6x = 12x - 9 - 2x² - 12x
4x² - 8x - 12x² + 6x - 12x + 9 + 2x² + 12x = 0
- 6x² - 2x + 9
Δ = b² - 4ac = 4 + 216 = 220
√Δ = √220 = 14,83
x₁ = (-b - √Δ) : 2a = (2 - 14,83) : -12 = 1,06
x₂ = (-b + √Δ) : 2a = (2 + 14,83) : -12 = -1,4