Odpowiedzi

2011-01-23T16:47:28+01:00
2011-01-23T17:22:41+01:00

[Fe(OH)2]3PO4
mFe= 56g 
mO= 16g
mH= 1g
mP= 31g
m[Fe(OH)2]3PO4= 3*[56g + 2*(16g+1g)] + 31g + 4*16g 
m[Fe(OH)2]3PO4= 3*[56g + 34g] + 31g + 64g 
m[Fe(OH)2]3PO4= 3* 90g + 95g = 270g + 95g = 365g

1 5 1