Odpowiedzi

2010-01-15T10:28:17+01:00
A) tlenek siarki(VI) - SO3
mS = 32u
mO = 16u
mSO3 = 32u + 3x16u = 80u

siarka:
80u - 100%
32u - x

32u x 100%
x = -------------- = 40%
80u
tlen:
80u - 100%
48u - x

48u x 100%
x = ------------- = 60%, albo po prostu 100% - 40% = 60%
80u

b)siarczek glinu - Al2S3
mAl = 2x27u = 54u
mS = 3x32u = 96u
mAl2S3 = 54u + 96u = 150u

glin:
150u - 100%
54u - x

54u x 100%
x = --------------- = 36%
150u

100% - 36% = 64%
6 4 6