Odpowiedzi

2010-01-17T14:31:33+01:00
3x-2(-5+y)-5[-3x+2(y-1)-10(5y-4)]=
3x + 10 - 2y -5(-3x + 2y - 2 - 50y + 40) =
3x + 10 - 2y + 15x - 10y + 10 +250y - 200 =
18x - 238y - 180
2010-01-17T14:39:56+01:00
3x-2(-5+y)-5[-3x+2(y-1)-10(5y-4)]=
3x + 10 - 2y -5(-3x + 2y - 2 - 50y + 40) =
3x + 10 - 2y + 15x - 10y + 10 +250y - 200 =
18x - 238y - 180
2010-01-17T14:44:09+01:00
3x-2(-5+y)-5[-3x+2(y-1)-10(5y-4)]=
3x+10-2y-5(-3x+2y-2-50y+40)=
3x+10-2y+15x-10y+10+250y-200=
18x+238y-180

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