Odpowiedzi

2010-01-17T16:00:13+01:00
A(2ab+b)-b(a-2ab+a)do potęgi =2a^2b+ab-b(a^2-4ab+a^2)=2a^2b+ab-a^2b+4ab^2-ab=a^2b+4ab^2
2010-01-17T16:14:29+01:00
A(2ab+b)-b(a-2ab+a)²=2a²b+ab-b(a-2ab+a)(a-2ab+a)=
2a²b+ab-b(a²-2a²b+a²-2a²b+4a²b²-2a²b+a²-2a²b+a²)=
2a²b+ab-b(4a²-8a²b+4a²b²)=
2a²b+ab-4a²b+8a²b²-4a²b³=
ab-2a²b+8a²b²-4a²b³