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2010-01-18T17:36:55+01:00
A) 1cm
P=4pir^2= 4pi1=4pi cm ^2
l=2pir=2pi cm

b) 3/4 m
P=4pir^2=4 pi9/16=9/4 pi m^2
l=2pir=3/2 pi m

c)2,2dm
P=4pir^2=19,36pi dm^2
l=2pir=4,4 pi dm
4 3 4
  • Użytkownik Zadane
2010-01-18T17:37:10+01:00
A.
r = 1 cm
l= 2πr
l = 2π
P = πr²
P = π*1²
p = π

b.
3/4 m = 75 cm
r = 75cm
l = 2πr
l = 2π * 75
l = 150π
P = πr²
P = π*75²
P = 5625π

c.
2,2dm = 22 cm
l = 2πr
l = 2π * 22
l = 44π

P = πr²
P = π * 22²
P = 484π
4 3 4
2010-01-18T17:38:40+01:00
A) P=πr²
P=π*1²
P=π cm²
l=2πr
l=2*π*1
l=2π cm
b)P=π*(3/4)²
P=9/16π m²
l=2*π*3/4
l=1,5π m
c)P=π*2,2²
P=4,84π dm²
l=2*π*2,2
l=4,4π dm
4 4 4