Odpowiedzi

2010-01-19T20:41:36+01:00
X+6y=1020
0,9x+6*0,8y=864

x=1020-6y
0,9*(1020-6y) +4,8y=864

918-5,4y+4,8y=864
0,6y=54
y=90

x+6*90=1020
x+540=1020
x=480

x=480
y=90
1 1 1
2010-01-19T20:45:12+01:00
X-cena stołu
y-cena krzesła

x+6y=1020
x-0,1x+6(y-0,2y)=846

x=1020-6y
0,9x+6*0,8y=846

0,9(1020-6y)+4,8y=846
918-5,4y+4,8y=846
-5,4y+4,8y=846-918
-0,6y=-72
y=120

x+6*120=1020
x+720=1020
x=1020-720
x=300
2010-01-19T20:50:47+01:00
X -cena stołu
y-cena krzesła

x+6y=1020
9/10x+8/10*6y=846/*10

x+6y=1020/(-8)
9x+48y=8460

-8x-48y=-8160
9x+48y=8460

x=300
6y=1020-300

x=300
y=120