Odpowiedzi

2010-01-23T14:31:26+01:00
3(x²-2x+3)-2(x²-5x-1) = dla x=2 2.
= 3x²-6x+9-2x²+10x+2 =
= x²+4x+11 =
= (2,2)² + 4*2,2 + 11 =
= 4,84 + 8,8 + 11 =
= 24,62

a(2ab-b)-b(a-2ab+a²) = dla a=0,1i b=-10
= 2a²b-ab-ab-2ab²-a²b =
= a²b-2ab-2ab² =
= ab(a-2-2b)=
= 0,1*(-10)[0,1-2-2*(-10)] =
= -1(0,1-2+20) =
= -(18,1) =
= -18,1