Odpowiedzi

2009-10-01T18:44:14+02:00
D-prekatna
a-bok kwadratu
d=a+2
d=a√2
a+2=a√2
a-a√2=-2
a(1-√2)=-2
a=-2/(1-√2)
a=2/(√2-1)
P=a²
P=(2/(√2-1))²=4/(2-2√2+1)=4/(3-2√2)