Odpowiedzi

2010-01-28T09:45:47+01:00
A)(?)+(2x² - 3xy)=6x²+xy-7
czyli 6x²+xy-7-(2x² - 3xy)
(?)=4x²+4xy-7
b)(5x²-4x+3)-(?) =10+x
10+x-5x²+4x-3=-5x²+5x+7
czyli 5x²-5x-7
c) (?)-(6ab-6a+6b)= 6ab-a+1
(?)-6ab+6a-6b= 6ab-a+1
6ab-a+1+6ab-6a+6b=12ab-7a+6b+1

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