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  • Użytkownik Zadane
2010-01-28T10:59:26+01:00
A)H2SO3
2x1u+1x32u+3x16u=2u+32u+48u=82u
siarka:
82u-100%
32u-x
x=32ux100%/82u=39.02%
tlen:
82u-100%
48u-x
x=48x100%/82u=58.53%
wodor:
100%-58.53%-39.02%=2.68%
b)H2SO4
2x1u+1x32u+4x16u=2u+32u+64u=98u
siarka:
98u - 100%
32u-x
x=32ux100%/98u=32.65%
tlen:
98u-100%
64u-x
x=64ux100%/98u=65.30%
wodor:
98u-100%
2u-x
x=2ux100%/98u=2.04%
c)HNO3
1x1u+1x14u+3x16u=1u+14u+48u=63u
wodor:
63u-100%
1u - x
x=1ux100%/63u=1.58%
azot:
63u-100%
14u-x
x=14ux100%/63u=22.22%
tlen:
63u-100%
48u-x
x=48ux100%/63u=76.19%
d)H3PO4
3x1u+1x31u+4x16u=3u+31u+64u=98u
fosfor
98u-100%
31u-x
x=31ux100%/98u=31.6%
tlen:
98u-100%
64u-x
x=64ux100%/98u=65.30%
wodor:
98u-100%
3u-x
x=3ux100%/98u=3.06%
e)H2S
2x1u+1x32u=2u+32u=34u
siarka:
34u-100%
32u-x
x=32ux100%/34u=94.1%
wodor:
100%-94.1%=5.9%
f)HCl
1x1u+1x35u=1u+35.5u=36.5u
chlor:
36.5u-100%
35.5u-x
x=35.5ux100%/36.5u=97.2%
wodor:
100%-97.2%=2.8%
g)H2CO3.
2x1u+1x12u+3x16u=2u+12u+48u=62u
wegiel:
62u-100%
12u-x
x=12ux100%/62u=19.35%
wodor:
62u-100%
2u-x
x=2ux100%/62u=3.22%
tlen:
62u-100%
48u-x
x=48ux100%/62u=77.21%