Odpowiedzi

  • Roma
  • Community Manager
2010-01-28T10:11:49+01:00
(x-3)(x-2)(x+2) = (x-1)³+6
(x-3)(x²-4) = x³-3x²+3x-1+6
x³-4x-3x²+12-x³+3x²-3x-5 = 0
-7x+7 = 0
-7x = -7 /:(-7)
x = 1