Odpowiedzi

2009-10-04T17:33:45+02:00
(log³4 + log³25):[4(log²2 - log2log5 + log²5)] = [(log4 + log25)(log²4 - log4log25 + log²25)]:[4(log²2 - log2log5 + log²5)] = [(2log2 + 2log5)(4log²2 - 4log2log5 + 4log²5)]:[4(log²2 - log2log5 + log²5)] = [8(log2 + log5)(log²2 - log2log5 + log²5)]:[4(log²2 - log2log5 + log²5)] = 2(log2 + log5) = 2log10 = 2