Odpowiedzi

2009-10-04T19:56:29+02:00
A) xy - 2y + x - 5 = 0
xy - 2y + x - 2 = 3
y(x-2) + 1(x-2) = 3
(x-2)(y+1) = 3
1 * 3
3 * 1
-1 * -3
-3 * 1

{x-2= 1
{y+1=3
{x=3
{y=2

{x-2=3
{y+1=1
{x=5
{y=0

{x-2=-1
{y+1=-3
{x=1
{y=-4

{x-2=-3
{y+1=-1
{x=-1
{y=-2

b)
x - y = xy
x - y - xy = 0 /+1
x - xy + 1 - y = 1
x(1-y) + 1(1-y)=1
(1-y)(x+1)=1
1 * 1
-1 * -1

{x+1 = 1
{1-y = 1
{x=0
{y=0

{x+1=-1
{1-y=-1
{x=-2
{y=2
8 4 8