Odpowiedzi

2009-10-05T17:00:48+02:00
(x-2)(x+2) + 2y = (x-2)² + y
3x + 2y = 11

x^2-4+2y=x^2-4x+4+y
3x+2y=11

2y-4=4+y-4x
3x+2y=11

y=8-4x
3x+2(8-4x)=11

y=8-4x
3x+16-8x=11

y=8-4x
-5x=-5

y=8-4x
x=1

y=8-4
x=1

y=4
x=1
1 5 1