Odpowiedzi

2010-01-31T15:32:21+01:00
A=(1,0)
B=(-2,-4)
C=(3,-4)

|AB| = √(-2-1)² + (-4 - 0)²
|AB|= 5

|AC| = √(3-1)² + (-4, 0)²
|AC| = 2√5

|BC| = √(3+2)² + (-4 +4)²
|BC| = 5

pzdr ;)
2010-01-31T15:33:20+01:00
|AB|= √(-4-0)²+(-2-1)²=√16+9=√25=5
|BC|=√(-4+4)²+(3+2)²=√25=5
|CA|=√(0+4)²+(1-3)²=√20=2√5