Odpowiedzi

2010-01-31T15:32:05+01:00
-4(2x+1)≥-(x-1)
-4*2x-4*1≥-x+1
-8x-4≥-x+1
-8x+x≥1+4
-7x≥5
x≤-5/7

x∈(-∞; -5/7>
2010-01-31T15:46:44+01:00
-4(2x+1)≥-(x-1)=-4*2x-4*1≥-x+1=-8x-4≥-x+1=-8x+x≥1+4=-7x≥5=x≤-5/7