Odpowiedzi

2010-01-31T19:24:56+01:00
4x-3(x+4)-12 = 4x-3x-12-12 = x-24
-4k-2(k+3)-14k = -4k-2k-6-14k = -20k-6
-(7k-3)-15(4k-8) = -7k+3-60k+120 = -67k+123
3c^-7c+15c(c-3) = 3c^-7c+15c^-45c = 18c^-52c
-2x^-4x(x-5)+14x^ = -2x^-4x^+20+14x^ = 12x^+20
2010-01-31T19:27:17+01:00
4x-3(x+4)-12=4x-3x- 12-12=x-24
-4k-2(k+3)-14k=-20k-6
-(7k-3)-15(4k-8)=-67k +123
3c^-7c+15c(c-3)=18c² -52c
-2x^-4x(x-5)+14x^=12x² +20