Odpowiedzi

2010-02-01T12:08:05+01:00
Zadanie na trojkat Pascala
...............1......1
............1......2.......1
..........1....3......3.......1
.......1.....4.....6......4.......1
(x+3)⁴=x⁴+4x³*3+6x²*3²+4x*3³+3⁴=
x⁴+12x³+54x²+108x+81

pozdrawiam

Hans
2010-02-01T12:12:18+01:00
(a+b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4

(x+3)^4 = x^4 + 4x^3*3 + 6x^2*3^2 + 4x*3^3+3^4
x^4 + 12x^3 + 54x^2 + 108x + 81