Odpowiedzi

2010-02-02T15:04:25+01:00
A) (a+b)-(2a-b)+(a-2b)= a+b-2a+b+a-2b = 0
b) (3x-y+1)-(x+y)+(y+x)= 3x-y+1-x-y+y+x = 3x -y +1
c) -(kx+ny)-(3kx+2ny)+(5kx-3ny)= -kx-ny-3kx-2ny+5kx-3ny = kx-6ny
d) ((2ab+a+3)-(3ab-a+3)=2ab+a+3-3ab+a-3= -ab+2a
122 3 122