Odpowiedzi

2009-04-08T15:09:37+02:00
W(x)=-x³+2x²-3x+a
a)
W(1)=4
-1+2-3+a=4
a=6
b)W(x)=-x³+2x²-3x+6
w(x)=(x-2)(-x²-3)
w(x)=-(x-2)(x²+3)
c)
-(x-2)(x²+3)=0
x=2