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  • Roma
  • Community Manager
2010-02-02T21:36:22+01:00
5x⁴ + 6x³ + x² = 0
x²(5x² + 6x + 1) = 0
x² = 0 v 5x² + 6x + 1 = 0

x² = 0
x₁ = 0

5x² + 6x + 1 = 0
Δ = 6² - 4*5*1 = 36 - 20 = 16
√Δ = 4
x₂ = - 6 - 4 / 2*5 = -10 / 10 = -1
x₃ = - 6 + 4 / 2*5 = -2 / 10 = -⅕

czyli
x₁ = 0
x₂ = -1
x₃ = -⅕
2 5 2